{"id":581,"date":"2016-10-07T10:37:05","date_gmt":"2016-10-07T13:37:05","guid":{"rendered":"http:\/\/www.galirows.com.br\/meublog\/programacao\/?p=581"},"modified":"2020-09-11T09:10:47","modified_gmt":"2020-09-11T12:10:47","slug":"exercicios-basicos-vetores","status":"publish","type":"post","link":"http:\/\/www.galirows.com.br\/meublog\/programacao\/exercicios-basicos-vetores\/","title":{"rendered":"Resolu\u00e7\u00e3o em linguagem C para exerc\u00edcios b\u00e1sicos com vetores"},"content":{"rendered":"<p>Escreva um programa que leia dois vetores com 10 elementos cada e gere um terceiro vetor de 20 elementos, cujos valores dever\u00e3o ser compostos pelos elementos intercalados dos dois outros vetores. Ao final o programa dever\u00e1 mostrar os dois vetores originais e o terceiro vetor com os valores intercalados.<\/p>\n<div data-canvas-width=\"442.43999999999994\">\n<pre class=\"lang:c decode:true\">#include &lt;stdio.h&gt;\n\n#define TAM 2 \/\/define constante\n\nint main() {\n    int vet1[TAM], vet2[TAM], vet3[TAM*2], i;\n\n    \/\/ler valores para o primeiro vetor\n    for (i = 0; i &lt; TAM; i++) {\n        scanf(\"%i\", &amp;vet1[i]);\n    }\n\n    \/\/ler valores para o segundo vetor\n    for (i = 0; i &lt; TAM; i++) {\n        scanf(\"%i\", &amp;vet2[i]);\n    }\n\n    \/\/preencher o terceiro vetor\n    for (i = 0; i &lt; TAM; i++) {\n        vet3[i*2] = vet1[i];\n    }\n    for (i = 0; i &lt; TAM; i++) {\n        vet3[i*2+1] = vet2[i];\n    }\n\n    \/\/mostra valores para o segundo vetor\n    printf(\"Vetor 1: \");\n    for (i = 0; i &lt; TAM; i++) {\n        printf(\"%i \", vet1[i]);\n    }\n    printf(\"\\n\");\n\n    \/\/mostra valores para o segundo vetor\n    printf(\"Vetor 2: \");\n    for (i = 0; i &lt; TAM; i++) {\n        printf(\"%i \", vet2[i]);\n    }\n    printf(\"\\n\");\n\n    \/\/mostra valores para o terceiro vetor\n    printf(\"Vetor 3: \");\n    for (i = 0; i &lt; TAM*2; i++) {\n        printf(\"%i \", vet3[i]);\n    }\n\n    return 0;\n}\n<\/pre>\n<p><strong>Resolu\u00e7\u00e3o em v\u00eddeo<\/strong><\/p>\n<p><iframe loading=\"lazy\" width=\"560\" height=\"315\" src=\"https:\/\/www.youtube.com\/embed\/S5OQnCMl73w\" allowfullscreen=\"allowfullscreen\" frameborder=\"0\"><\/iframe><\/p>\n<\/div>\n<div data-canvas-width=\"442.43999999999994\"><strong>Link para o v\u00eddeo:<\/strong> <a href=\"https:\/\/youtu.be\/S5OQnCMl73w\" target=\"_blank\" rel=\"noopener noreferrer\">https:\/\/youtu.be\/S5OQnCMl73w<\/a><\/div>\n<div data-canvas-width=\"442.43999999999994\"><\/div>\n<div data-canvas-width=\"442.43999999999994\">\n<hr \/>\n<\/div>\n<div data-canvas-width=\"442.43999999999994\"><\/div>\n<div data-canvas-width=\"442.43999999999994\">\n<div data-canvas-width=\"489.38000000000005\">Escreva um programa que receba do usu\u00e1rio um vetor com 20 valores inteiros e apresente o maior, o menor e suas respectivas posi\u00e7\u00f5es em que os mesmos foram informados. Caso existam n\u00fameros iguais mostre a posi\u00e7\u00e3o da primeira ocorr\u00eancia.<\/div>\n<\/div>\n<div data-canvas-width=\"241.94\"><\/div>\n<div data-canvas-width=\"241.94\">\n<div data-canvas-width=\"442.43999999999994\">\n<pre class=\"lang:c decode:true\">#include &lt;stdio.h&gt;\n\n#define TAM 5 \/\/cria uma constante\n\nint main() {\n    int vet[TAM], i, maior, posMaior, menor, posMenor;\n\n    \/\/preenche o vetor\n    for (i = 0; i &lt; TAM; i++) {\n        scanf(\"%i\", &amp;vet[i]);\n    }\n\n    \/\/encontra o maior valor\n    maior    = vet[0];\n    posMaior = 0;\n    for (i = 1; i &lt; TAM; i++) {\n        if (vet[i] &gt; maior) {\n            maior    = vet[i];\n            posMaior = i;\n        }\n    }\n\n    \/\/encontra o menor valor\n    menor    = vet[0];\n    posMenor = 0;\n    for (i = 1; i &lt; TAM; i++) {\n        if (vet[i] &lt; menor) {\n            menor    = vet[i];\n            posMenor = i;\n        }\n    }\n\n    \/\/mostra o vetor\n    printf(\"Vetor: \");\n    for (i = 0; i &lt; TAM; i++) {\n        printf(\"%i \", vet[i]);\n    }\n\n    printf(\"\\nMaior valor: %i - posicao: %i\", maior, posMaior+1);\n    printf(\"\\nMenor valor: %i - posicao: %i\", menor, posMenor+1);\n\n    return 0;\n}\n<\/pre>\n<p>Teste o c\u00f3digo em: <a href=\"https:\/\/ideone.com\/JpQqQm\">https:\/\/ideone.com\/JpQqQm<\/a><\/p>\n<p><strong>Resolu\u00e7\u00e3o em v\u00eddeo<\/strong><\/p>\n<p><iframe loading=\"lazy\" width=\"560\" height=\"315\" src=\"https:\/\/www.youtube.com\/embed\/JGu84T1QPHU\" allowfullscreen=\"allowfullscreen\" frameborder=\"0\"><\/iframe><\/p>\n<\/div>\n<div data-canvas-width=\"442.43999999999994\"><strong>Link para o v\u00eddeo:<\/strong> <a href=\"https:\/\/youtu.be\/JGu84T1QPHU\" target=\"_blank\" rel=\"noopener noreferrer\">https:\/\/youtu.be\/JGu84T1QPHU<\/a><\/div>\n<div data-canvas-width=\"442.43999999999994\"><\/div>\n<div data-canvas-width=\"442.43999999999994\">\n<hr \/>\n<\/div>\n<div data-canvas-width=\"71.8\"><\/div>\n<div data-canvas-width=\"218.61999999999998\">Escreva um programa que leia um vetor de 100 elementos.O programa deve informar a quantidade de n\u00fameros \u00edmpares existentes no vetor. Os\u00a0 valores armazenados no vetor ser\u00e3o informados pelo usu\u00e1rio, ou gerados pelo\u00a0 computador.<\/div>\n<\/div>\n<div data-canvas-width=\"218.61999999999998\"><\/div>\n<div data-canvas-width=\"218.61999999999998\"><strong>C\u00f3digo com valores lidos do usu\u00e1rio<\/strong><\/div>\n<div data-canvas-width=\"218.61999999999998\"><\/div>\n<div data-canvas-width=\"218.61999999999998\">\n<div data-canvas-width=\"442.43999999999994\">\n<pre class=\"lang:c decode:true \">#include &lt;stdio.h&gt;\n\n#define TAM 3\n\nint main() {\n    int vet[TAM], i, impares = 0;\n\n    \/\/ler valores para o vetor\n    for (i = 0; i &lt; TAM; i++) {\n        scanf(\"%i\", &amp;vet[i]);\n    }\n\n    \/\/mostrar valores do vetor\n    printf(\"Vetor: \");\n    for (i = 0; i &lt; TAM; i++) {\n        printf(\"%i \", vet[i]);\n    }\n\n    \/\/conta impares\n    for (i = 0; i &lt; TAM; i++) {\n        if (vet[i]%2 == 1) {   \/\/testa se impar\n            impares++;\n        }\n    }\n\n    printf(\"\\nImpares: %i\", impares);\n\n    return 0;\n}\n<\/pre>\n<p><strong>C\u00f3digo com valores gerados aleatoriamente<\/strong><\/p>\n<\/div>\n<\/div>\n<div data-canvas-width=\"442.43999999999994\">\n<pre class=\"lang:c decode:true\">#include &lt;stdio.h&gt;\n#include &lt;stdlib.h&gt;\n#include &lt;time.h&gt;\n\n#define TAM 30\n\nint main()\n{\n    int vet[TAM], i, impares = 0;\n\n    srand(time(NULL)); \/\/planta uma nova semente\n\n    \/\/gera valores aleatorio para o vetor\n    for (i = 0; i &lt; TAM; i++) {\n        vet[i] = rand()%6 + 1;  \/\/gera valores entre 1 e 6\n    }\n\n    \/\/mostrar valores do vetor\n    printf(\"Vetor: \");\n    for (i = 0; i &lt; TAM; i++) {\n        printf(\"%i \", vet[i]);\n    }\n\n    \/\/conta impares\n    for (i = 0; i &lt; TAM; i++) {\n        if (vet[i]%2 == 1) {   \/\/testa se impar\n            impares++;\n        }\n    }\n\n    printf(\"\\nImpares: %i\", impares);\n\n    return 0;\n}<\/pre>\n<\/div>\n<p><strong>Resolu\u00e7\u00e3o em v\u00eddeo<\/strong><\/p>\n<p><iframe loading=\"lazy\" width=\"560\" height=\"315\" src=\"https:\/\/www.youtube.com\/embed\/FvsKVLqvWWg\" allowfullscreen=\"allowfullscreen\" frameborder=\"0\"><\/iframe><\/p>\n<div data-canvas-width=\"442.43999999999994\"><strong>Link para o v\u00eddeo:<\/strong> <a href=\"https:\/\/youtu.be\/FvsKVLqvWWg\" target=\"_blank\" rel=\"noopener noreferrer\">https:\/\/youtu.be\/FvsKVLqvWWg<\/a><\/div>\n<div data-canvas-width=\"218.61999999999998\">\n<div data-canvas-width=\"442.43999999999994\"><\/div>\n<div data-canvas-width=\"442.43999999999994\">\n<hr \/>\n<\/div>\n<div data-canvas-width=\"442.43999999999994\"><\/div>\n<\/div>\n<div data-canvas-width=\"218.61999999999998\">\n<div data-canvas-width=\"674.8399999999998\">Dadas as temperaturas que foram registradas diariamente durante uma semana,<\/div>\n<div data-canvas-width=\"173.16\">deseja-se determinar em quantos dias dessa semana a temperatura esteve acima da m\u00e9dia. Escreva um programa (utilizando vetores) para calcular esta informa\u00e7\u00e3o.<\/div>\n<\/div>\n<div data-canvas-width=\"173.16\">\n<div data-canvas-width=\"442.43999999999994\"><\/div>\n<div data-canvas-width=\"442.43999999999994\">\n<pre class=\"lang:c decode:true \">#include &lt;stdio.h&gt;\n#include &lt;stdlib.h&gt;\n#include &lt;time.h&gt;\n\n#define TAM 7\n\nint main() {\n    int vet[TAM], i, acimaMedia = 0, soma = 0;\n    float media;\n\n    srand(time(NULL)); \/\/planta uma nova semente\n\n    \/\/gera valores aleatorio para o vetor\n    for (i = 0; i &lt; TAM; i++) {\n        vet[i] = rand()%51;\n    }\n\n    \/\/determina a media\n    for (i = 0; i &lt; TAM; i++) {\n        soma = soma + vet[i];\n    }\n    media = soma \/ (float)TAM;\n\n    \/\/determina quantos valores estao acima da media\n    for (i = 0; i &lt; TAM; i++) {\n        if (vet[i] &gt; media) {\n            acimaMedia++;\n        }\n    }\n\n    \/\/mostrar valores do vetor\n    printf(\"Vetor: \");\n    for (i = 0; i &lt; TAM; i++) {\n        printf(\"%i \", vet[i]);\n    }\n\n    printf(\"\\nMedia: %f\", media);\n    printf(\"\\nAcima da media: %i\", acimaMedia);\n\n    return 0;\n}<\/pre>\n<p><strong>Resolu\u00e7\u00e3o em v\u00eddeo<\/strong><\/p>\n<p><iframe loading=\"lazy\" width=\"560\" height=\"315\" src=\"https:\/\/www.youtube.com\/embed\/tZCbxHgUpL8\" allowfullscreen=\"allowfullscreen\" frameborder=\"0\"><\/iframe><\/p>\n<\/div>\n<div data-canvas-width=\"442.43999999999994\"><strong>Link para o v\u00eddeo:<\/strong> <a href=\"https:\/\/youtu.be\/tZCbxHgUpL8\" target=\"_blank\" rel=\"noopener noreferrer\">https:\/\/youtu.be\/tZCbxHgUpL8<\/a><\/div>\n<\/div>\n<div data-canvas-width=\"173.16\"><\/div>\n","protected":false},"excerpt":{"rendered":"<p>Escreva um programa que leia dois vetores com 10 elementos cada e gere um terceiro vetor de 20 elementos, cujos valores dever\u00e3o ser compostos pelos elementos intercalados dos dois outros vetores. Ao final o programa dever\u00e1 mostrar os dois vetores originais e o terceiro vetor com os valores intercalados. #include &lt;stdio.h&gt; #define TAM 2 \/\/define [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[3,4],"tags":[36,37,14],"class_list":["post-581","post","type-post","status-publish","format-standard","hentry","category-c","category-videos","tag-for","tag-if","tag-vetor"],"aioseo_notices":[],"amp_enabled":true,"_links":{"self":[{"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/posts\/581","targetHints":{"allow":["GET"]}}],"collection":[{"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/comments?post=581"}],"version-history":[{"count":8,"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/posts\/581\/revisions"}],"predecessor-version":[{"id":1071,"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/posts\/581\/revisions\/1071"}],"wp:attachment":[{"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/media?parent=581"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/categories?post=581"},{"taxonomy":"post_tag","embeddable":true,"href":"http:\/\/www.galirows.com.br\/meublog\/programacao\/wp-json\/wp\/v2\/tags?post=581"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}